(A) In positron emission,a proton $(p)$ is converted into a neutron $(n)$ and a positron $(e^+)$ is emitted: $p \rightarrow n + e^+$. Since the total

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(A) In positron emission,a proton $(p)$ is converted into a neutron $(n)$ and a positron $(e^+)$ is emitted: $p \rightarrow n + e^+$. Since the total number of nucleons (protons + neutrons) remains constant during this process,the mass number $(A)$ of the resulting isotope remains the same. Therefore,the correct option is $(A)$.

Class 12 Chemistry Nuclear Chemistry Nucleus (Stability and Reaction)

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Positron emission results from the transformation of one nuclear proton into a neutron. The isotope thus produced possesses

A
Same mass number
B
Higher nuclear charge
C
Intense radioactivity
D
No radioactivity

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Nuclear Chemistry

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Nucleus (Stability and Reaction)

Which among the following minerals contains a radioactive element?

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The measure of binding energy of a nucleus is the

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Assertion : Nuclear binding energy per nucleon is in the order $_4^9Be > \,_3^7Li > \,_2^4He$.
Reason : Binding energy per nucleon increases linearly with the difference in the number of neutrons and protons.

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The number of neutrons in the parent nucleus which gives $^{14}N$ on $\beta$-emission is

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Which of the following can be used for carrying out a nuclear fission reaction?

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Positron emission results from the transformation of one nuclear proton into a neutron. The isotope thus produced possesses

Similar Questions

Which among the following minerals contains a radioactive element?

The measure of binding energy of a nucleus is the

Assertion : Nuclear binding energy per nucleon is in the order $_4^9Be > \,_3^7Li > \,_2^4He$.Reason : Binding energy per nucleon increases linearly with the difference in the number of neutrons and protons.

The number of neutrons in the parent nucleus which gives $^{14}N$ on $\beta$-emission is

Which of the following can be used for carrying out a nuclear fission reaction?

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Assertion : Nuclear binding energy per nucleon is in the order $_4^9Be > \,_3^7Li > \,_2^4He$.
Reason : Binding energy per nucleon increases linearly with the difference in the number of neutrons and protons.